3.14.86 \(\int \frac {1}{(1-2 x) (2+3 x) (3+5 x)^3} \, dx\)

Optimal. Leaf size=53 \[ \frac {155}{121 (5 x+3)}-\frac {5}{22 (5 x+3)^2}-\frac {8 \log (1-2 x)}{9317}-\frac {27}{7} \log (3 x+2)+\frac {5135 \log (5 x+3)}{1331} \]

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Rubi [A]  time = 0.02, antiderivative size = 53, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 1, integrand size = 22, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.045, Rules used = {72} \begin {gather*} \frac {155}{121 (5 x+3)}-\frac {5}{22 (5 x+3)^2}-\frac {8 \log (1-2 x)}{9317}-\frac {27}{7} \log (3 x+2)+\frac {5135 \log (5 x+3)}{1331} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[1/((1 - 2*x)*(2 + 3*x)*(3 + 5*x)^3),x]

[Out]

-5/(22*(3 + 5*x)^2) + 155/(121*(3 + 5*x)) - (8*Log[1 - 2*x])/9317 - (27*Log[2 + 3*x])/7 + (5135*Log[3 + 5*x])/
1331

Rule 72

Int[((e_.) + (f_.)*(x_))^(p_.)/(((a_.) + (b_.)*(x_))*((c_.) + (d_.)*(x_))), x_Symbol] :> Int[ExpandIntegrand[(
e + f*x)^p/((a + b*x)*(c + d*x)), x], x] /; FreeQ[{a, b, c, d, e, f}, x] && IntegerQ[p]

Rubi steps

\begin {align*} \int \frac {1}{(1-2 x) (2+3 x) (3+5 x)^3} \, dx &=\int \left (-\frac {16}{9317 (-1+2 x)}-\frac {81}{7 (2+3 x)}+\frac {25}{11 (3+5 x)^3}-\frac {775}{121 (3+5 x)^2}+\frac {25675}{1331 (3+5 x)}\right ) \, dx\\ &=-\frac {5}{22 (3+5 x)^2}+\frac {155}{121 (3+5 x)}-\frac {8 \log (1-2 x)}{9317}-\frac {27}{7} \log (2+3 x)+\frac {5135 \log (3+5 x)}{1331}\\ \end {align*}

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Mathematica [A]  time = 0.05, size = 43, normalized size = 0.81 \begin {gather*} \frac {\frac {1925 (62 x+35)}{(5 x+3)^2}-16 \log (1-2 x)-71874 \log (6 x+4)+71890 \log (10 x+6)}{18634} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[1/((1 - 2*x)*(2 + 3*x)*(3 + 5*x)^3),x]

[Out]

((1925*(35 + 62*x))/(3 + 5*x)^2 - 16*Log[1 - 2*x] - 71874*Log[4 + 6*x] + 71890*Log[6 + 10*x])/18634

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IntegrateAlgebraic [F]  time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \frac {1}{(1-2 x) (2+3 x) (3+5 x)^3} \, dx \end {gather*}

Verification is not applicable to the result.

[In]

IntegrateAlgebraic[1/((1 - 2*x)*(2 + 3*x)*(3 + 5*x)^3),x]

[Out]

IntegrateAlgebraic[1/((1 - 2*x)*(2 + 3*x)*(3 + 5*x)^3), x]

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fricas [A]  time = 1.37, size = 73, normalized size = 1.38 \begin {gather*} \frac {71890 \, {\left (25 \, x^{2} + 30 \, x + 9\right )} \log \left (5 \, x + 3\right ) - 71874 \, {\left (25 \, x^{2} + 30 \, x + 9\right )} \log \left (3 \, x + 2\right ) - 16 \, {\left (25 \, x^{2} + 30 \, x + 9\right )} \log \left (2 \, x - 1\right ) + 119350 \, x + 67375}{18634 \, {\left (25 \, x^{2} + 30 \, x + 9\right )}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1-2*x)/(2+3*x)/(3+5*x)^3,x, algorithm="fricas")

[Out]

1/18634*(71890*(25*x^2 + 30*x + 9)*log(5*x + 3) - 71874*(25*x^2 + 30*x + 9)*log(3*x + 2) - 16*(25*x^2 + 30*x +
9)*log(2*x - 1) + 119350*x + 67375)/(25*x^2 + 30*x + 9)

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giac [A]  time = 0.86, size = 42, normalized size = 0.79 \begin {gather*} \frac {25 \, {\left (62 \, x + 35\right )}}{242 \, {\left (5 \, x + 3\right )}^{2}} + \frac {5135}{1331} \, \log \left ({\left | 5 \, x + 3 \right |}\right ) - \frac {27}{7} \, \log \left ({\left | 3 \, x + 2 \right |}\right ) - \frac {8}{9317} \, \log \left ({\left | 2 \, x - 1 \right |}\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1-2*x)/(2+3*x)/(3+5*x)^3,x, algorithm="giac")

[Out]

25/242*(62*x + 35)/(5*x + 3)^2 + 5135/1331*log(abs(5*x + 3)) - 27/7*log(abs(3*x + 2)) - 8/9317*log(abs(2*x - 1
))

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maple [A]  time = 0.01, size = 44, normalized size = 0.83 \begin {gather*} -\frac {8 \ln \left (2 x -1\right )}{9317}-\frac {27 \ln \left (3 x +2\right )}{7}+\frac {5135 \ln \left (5 x +3\right )}{1331}-\frac {5}{22 \left (5 x +3\right )^{2}}+\frac {155}{121 \left (5 x +3\right )} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(1/(1-2*x)/(3*x+2)/(5*x+3)^3,x)

[Out]

-5/22/(5*x+3)^2+155/121/(5*x+3)+5135/1331*ln(5*x+3)-27/7*ln(3*x+2)-8/9317*ln(2*x-1)

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maxima [A]  time = 0.51, size = 44, normalized size = 0.83 \begin {gather*} \frac {25 \, {\left (62 \, x + 35\right )}}{242 \, {\left (25 \, x^{2} + 30 \, x + 9\right )}} + \frac {5135}{1331} \, \log \left (5 \, x + 3\right ) - \frac {27}{7} \, \log \left (3 \, x + 2\right ) - \frac {8}{9317} \, \log \left (2 \, x - 1\right ) \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1-2*x)/(2+3*x)/(3+5*x)^3,x, algorithm="maxima")

[Out]

25/242*(62*x + 35)/(25*x^2 + 30*x + 9) + 5135/1331*log(5*x + 3) - 27/7*log(3*x + 2) - 8/9317*log(2*x - 1)

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mupad [B]  time = 0.04, size = 35, normalized size = 0.66 \begin {gather*} \frac {5135\,\ln \left (x+\frac {3}{5}\right )}{1331}-\frac {27\,\ln \left (x+\frac {2}{3}\right )}{7}-\frac {8\,\ln \left (x-\frac {1}{2}\right )}{9317}+\frac {\frac {31\,x}{121}+\frac {35}{242}}{x^2+\frac {6\,x}{5}+\frac {9}{25}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(-1/((2*x - 1)*(3*x + 2)*(5*x + 3)^3),x)

[Out]

(5135*log(x + 3/5))/1331 - (27*log(x + 2/3))/7 - (8*log(x - 1/2))/9317 + ((31*x)/121 + 35/242)/((6*x)/5 + x^2
+ 9/25)

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sympy [A]  time = 0.20, size = 46, normalized size = 0.87 \begin {gather*} - \frac {- 1550 x - 875}{6050 x^{2} + 7260 x + 2178} - \frac {8 \log {\left (x - \frac {1}{2} \right )}}{9317} + \frac {5135 \log {\left (x + \frac {3}{5} \right )}}{1331} - \frac {27 \log {\left (x + \frac {2}{3} \right )}}{7} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(1/(1-2*x)/(2+3*x)/(3+5*x)**3,x)

[Out]

-(-1550*x - 875)/(6050*x**2 + 7260*x + 2178) - 8*log(x - 1/2)/9317 + 5135*log(x + 3/5)/1331 - 27*log(x + 2/3)/
7

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